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Solving QE's by factoring

x

x {}^(2) - 11x + 28 = 0
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Answer:

The factored form of this is (x - 7)(x -4)

Explanation:

In order to factor quadratic equaitons with a 1 as the first coefficient, we look for two numbers that multiply to the last number (28), but add up to the middle number (-11). To do this, we often list the factors of the last number.

Factors of 28

1, 28

-1, -28

2, 14

-2, -14

4, 7

-4, -7

The numbers -4 and -7 satisfy this requirement and are therefore the numbers we want. Now we stick them into parenthesis along with x terms in the front like this:

(x - 7)(x -4)

And that is the fully factored form.

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User Gord Thompson
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