Question

The sensor in the torso of a crash test dummy records the magnitude znd direction of the net force acting on the dummy.If the dummy is thrown forward with a force of 130.0N while simultandously being hit from the side wigh a force of 4500.0N,what force will the sensor report

Answer 1

Answer : The force will be 4501.9

We can see that, two forces acting on the dummy in two different direction.

We know that, here two forces are given in perpendicular direction with each other.

We know the force is the vector addition law so, we will use the Pythagoras theorem for the resultant of the vectors

Now, the net force is

`F_(net) = \sqrt{{F_(1)}^(2)+ {F_(2)}^(2)}`

Two forces is given,

`F_(1) = 130.0 N`

`F_(2) = 4500.0 N`

Now, the net force is

`F_(net) = \sqrt{(130)^(2)+ (4500)^(2)}N`

`F_(net) = √(20266900)N`

`F_(net) = 4501.9 N`

Hence, the force will 4501.9 N