asked 235k views
5 votes
Which function in the vertex form is equivalent to f(x)=x^2+6x+3

asked
User The Jug
by
8.4k points

2 Answers

4 votes

Answer:

B. f(x) = (x + 3)2 − 6


Explanation:


answered
User Goper Leo Zosa
by
8.3k points
4 votes

Answer:


f(x)=(x+3)^2-6

Explanation:

We have been given a function
f(x)=x^2+6x+3. We are asked to find the function equivalent to our given function in vertex form.

To convert our given function in vertex form, we need to complete the square for our given function as:

Add and subtract
((b)/(2))^2 from equation:


((b)/(2))^2=((6)/(2))^=3^2=9


f(x)=(x^2+6x+9)+3-9


f(x)=(x^2+2\cdot 3x+3^2)-6


f(x)=(x+3)^2-6

Therefore, the
f(x)=(x+3)^2-6 is equivalent to our given function in vertex form.

answered
User Matt Sgarlata
by
8.4k points

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