Question

Herky was given the following system of equations to solve.

3x-2y=17
x-3y=1
What is the solution to the system?
(2,7)
(20/7,67/7)
(7,2)
(67/7,20/7)

Answer 1

Option 3 (7,2) is right answer.

Explanation:

Given two equations

3x-2y=17 ... i

x-3y=1 ... ii

We can solve this by elimination.

coefficients of x are 3 and 1 with LCD = 3

Hence multiply ii equation by 3

3x-9y = 3 ... iv

3x-2y = 17 ... i

Subtract i from iv

-7y = -14

Divide by -7

y =2

Substitute in ii

x-3(2) = 1

x=7

Hence solution is (7,2)

Verify:

We can verify our solution by substituting in i and ii.

3(7)-2(2) = 17 and 7-6 =1

Verified