Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high did it travel?

Question

asked Jul 18, 2019 42.2k views

1 Answer

Spectral Instance · Answer 1 · 2019-07-23T17:48:57+0000

Answer:

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Step-by-step explanation:

As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.

sin 50 =
(OM)/(OP)

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meter

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.