Question

an investigation is currently worth 1.2 X10^7 dollars twenty years ago the investment was worth 9.6X10^5 dollars how many times greater in the value of the investment today than the value of the investment twenty years ago A. 0.125 B. 12.5 C. 125 D. 12,500

Answer 1

As given,

Current value =
`1.2*10^(7)` dollars

Twenty years ago value was =
`9.6*10^(5)` dollars

suppose x times the investment has increased, so,

`9.6*10^(5)`*x=
`1.2*10^(7)`

x =
`\frac{1.2*10^(7)} {9.6*10^(5)}`

this gives x = 12.5 times.

Hence, option B is the correct answer.