Question

What is the perimeter of triangle ABC round each step by the nearest 10th see image. Thanks so much

Answer 1

Perimeter of the triangle ABC is 18.7 units.

Coordinate of the point A is (4, -1), B is (-1, 4) and C is (0, -3).

Length of the side AB =
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}`

AB =
`\sqrt{(-1-4)^(2)+(4+1)^(2)} =√(50)`

AB = 7.07 units = 7.1 units ( rounded to the nearest 10th)

Length of the side BC =
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}`

BC =
`\sqrt{(0+1)^(2)+(-3-4)^(2)}`

BC =
`√(50)`

BC = 7.07 units = 7.1 units ( rounded to the nearest 10th)

Length of the side CA =
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}`

CA =
`\sqrt{(4-0)^(2)+(-1+3)^(2)}`

CA =
`√(20)`

CA = 4.47 units = 4.5 ( rounded to the nearest 10th)

Perimeter of the triangle ABC = sum of all three sides = (7.1 + 7.1 + 4.5) units = 18.7 units