Question

A triangle has the perimeter of 31". The longest side is 1" less than twice the shortest side and the 3rd side is 4" longer than the shortest site. Find the lengths of the sides

Answer 1

X = short side
2x-1 = longest side
X+ 4 = 3rd side

Add them together and set them equal to 31

X+2x-1+x+4=31

4x+ 3=31

Subtract 3 from both sides
4x = 28
X=7

The short side is 7. The long side is 2(7)-1=13
The third side is 7+4 =11