Answer:
(3±√147, 0) ≈ (-9.124, 0) and (15.124, 0)
Explanation:
The points (x, 0) satisfy the distance formula:
d = 14 = √((x -3)² +(0+7)²)
196 = (x -3)² +49 . . . . . square both sides
147 = (x -3)² . . . . . . . . . subtract 49
3 ±√147 = x . . . . . . . . . take the square root and add 3
The points at distance 14 from (3, -7) on the x-axis are (3±√147, 0).