Question

Writing net ionic equation!! 2FeBr3(aq) + 3Na2S(aq) ->Fe2S3(s)+6NaBr(aq)

Answer 1

Net ionic equation is
`2Fe^(3+)(aq.)+3S^(2-)(aq.)\rightarrow Fe_(2)S_(3)(s)`

Step-by-step explanation:

First write total ionic equation and then remove spectator ions from both side of equation to get net ionic equation. To write total ionic equation, separate all aqueous species into their constituting ions.

Total ionic equation-

`6Na^(+)(aq.)+3S^(2-)(aq.)+2Fe^(3+)(aq.)+6Br^(-)(aq.)\rightarrow Fe_(2)S_(3)(s)+6Na^(+)(aq.)+6Br^(-)(aq.)`

Here
`Na^(+)and Br^(-)` are spectator ions as they are presnt on both side of equation.

Hence net ionic equation is
`2Fe^(3+)(aq.)+3S^(2-)(aq.)\rightarrow Fe_(2)S_(3)(s)`

Answer 2

Balanced chemical reaction:

2FeBr₃(aq) + 3Na₂S(aq) → Fe₂S₃(s) + 6NaBr(aq).

Ionic reaction:

2Fe³⁺(aq) + 3Br⁻(aq) + 6Na⁺(aq) + 3S²⁻(aq) → Fe₂S₃(s) + 6Na⁺(aq) + 6Br⁻(aq).

Net ionic reaction: 2Fe³⁺(aq) + 3S²⁻(aq) → Fe₂S₃(s).

FeBr₃ - iron(III) bromide.

Na₂S - sodium sulfide.

Fe₂S₃ - iron(III) sulfide.

NaBr - sodium bromide.