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Answer question please

Answer question please
asked 152k views
2 votes
Answer question please

Answer question please-example-1
asked
User Sylvan LE DEUNFF
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8.0k points

1 Answer

7 votes

∠EFH = 6y + 14

since HF bisects ∠GFI then ∠GFH = ∠HFI = 2y + 6

hence ∠EFH = ∠EFG + ∠GFH = 4y + 8 + 2y + 6 = 6y + 14


answered
User Lav Vishwakarma
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