Question

Given the table of candy distibutions below, find P(not green), the probability of selecting anything but a green candy at random from a large bag

Answer 1

B is the answer for you math question.

Answer 2

Answer: 0.84

Explanation:

From the given table of probability distribution P (green)= 0.16

Since , the sum of all the probabilities of all the events in a particular probability distribution is 1.

Therefore, The probability of selecting anything but a green candy at random from a large bag is given by :-

`\text{P(not green)=1-P(green)}\\\\\Rightarrow\text{P(not green)}=1-0.16\\\\\Rightarrow\text{P(not green)}=0.84`

Hence, the probability of selecting anything but a green candy at random from a large bag = 0.84