Question

a rock fell from a cliff at 108 feet high and landed on an embankment feet from the ground. find the amount if time it would have taken the rock to fall.

Answer 1

To solve this problem we will directly use the formula:

`h=(1)/(2)gt^2`..........Equation 1

where symbols have their usual meanings.

Here g=32.2 ft/s^2 and h=108 feet

Therefore, from Equation 1 we will get:

`t=\sqrt{(2h)/(g)}`....Equation 2

Plugging in the values in Equation 2 we get:

`t=\sqrt{(2* 108)/(32.2)}\approx 2.59` seconds.

Therefore, the amount of time it would have taken the rock to fall is 2.59 seconds.