Question

A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature of the gas is raised to 235 degrees kelvin, what's the new pressure of the gas? (Assume that there's no change in volume.)

A. 854.46 kPa
B. 3.636 kPa
C. 1.702 kPa
D. 510 kPa
A. 854.46 kPa
B. 3.636 kPa
C. 1.702 kPa
D. 510 kPa
A. liquid to a solid.
B. liquid to a gas.
C. gas to a solid.
D. gas to a liquid

Answer 1

Answer: The new pressure of the gas is (A) 854.46 kPa.

The pressure of a given mass of gas at the absolute temperature 110 degrees K is 400 kPa.

The temperature is raised to 235 degrees K with constant volume.

Therefore,

Initial pressure
`P_(1)=400kPa`

Initial temperature
`T_(1)=110K`

Final temperature
`T_(2)=235K`

Final pressure
`P_(2)=?`

According to pressure law of gas,

`(P_(1) )/(T_(1) )=(P_(2) )/(T_(2) )` ( at constant volume)
`P_(2)=(P_(1)T_(2) )/(T_(1) )`

`P_(2)=(400X235)/(110)`

`P_(2)=854.46kPa`

Thus, the required new pressure of the gas is 854.46 kPa.