Question

Calculate the ratio of effusion rates of cl2 to o2

Answer 1

Hey There!:

Molar mass O2 => 32.0 g/mol

Molar mass Cl2 => 71.0 g/mol

effusion rate α 1 / (√ molar mass )

E Cl2 / E O2 = √ molar mass O2 / √ molar mass Cl2

E Cl2 / E O2 = ( √ 32.0 ) / ( √ 71.0 )

=> 0.671

Hope that helps!

Answer 2

Answer: The ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671

Step-by-step explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

`\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}`

We are given:

Molar mass of chlorine gas = 71 g/mol

Molar mass of oxygen gas = 32 g/mol

By taking their ratio, we get:

`(Rate_(Cl_2))/(Rate_(O_2))=\sqrt{(M_(O_2))/(M_(Cl_2))}`

`(Rate_(Cl_2))/(Rate_(O_2))=\sqrt{(32)/(71)}\\\\(Rate_(Cl_2))/(Rate_(O_2))=0.671`

Hence, the ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671