Question

X^2-4y^2=0

A.(x+4y)(x-y)

B. (x-4y)(x+y)

C. (x+2y)(x-2y)
D. (x-2y)(x-2y)

Answer 1

`x^(2)`-4
`y^(2)` = 0

Solution

Here we have to find the factors.

`x^(2)  - 4y^(2) = 0`

Here we can write 4y^2 as (2y)^2

`x^(2)  - (2y)^(2)  = 0`

Now we have to use the formula, a^2 - b^2 = (a + b)(a - b)

Here a = x and b = 2y

Therefore, we get

(x + 2y)(x -2y)

Hence, the answer isC. (x + 2y)(x -2y)