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Can you work out G and H for me please. preferably telling me how you did it aswell

Can you work out G and H for me please. preferably telling me how you did it aswell-example-1

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abd is a right angled triangle so by pythagoras we know

{g}^(2) = {11}^(2) + {13}^(2) \\ {g}^(2) = 290 \\ g = √(290) \: or \: g = 17.03cm
and to calculate h we need to use the sine rule

(h)/( \sin(22) ) = (g)/( \sin(32) ) \\ (h)/( \sin(22) ) = (17.03)/( \sin(32) ) \\ h = (17.03)/( \sin(32) ) * \sin(22) \\ h = 12.04cm
i hope this helps
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User Jeannie
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