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How much heat is absorbed when 100.0g of ice is melted?

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The quantity of heat absorbed is 33.4 kJ.

ΔH_fus = 334 J·g⁻¹

q = mΔH_fus = 100.0 g × 334 J·g⁻¹ = 3.34 × 10⁴ J = 33.4 kJ

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User Amar
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