Evaluate the following log32-log64+log16

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asked May 20, 2019 189k views

2 Answers

Cavila · Answer 1 · 2019-05-26T14:19:41+0000

Using properties of logarithms:

log(m+n) = log(m.n)

log(m-n) = log (m/n)

we get,

log(32x16/64)

On simplifying:

log(8)

and 8= 2^3

therefore,

log(2^3)

again using another property for exponents in logarithms we get:

3 log 2 <---- Answer

Evaluate the following log32-log64+log16

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