Question

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Answer 1

`5\left((1+i)/(1-i)\right)^6+6\left((1-i)/(1+i)\right)^5=\\\\5\left(((1+i)^2)/(1+1)\right)^6+6\left(((1-i)^2)/(1+1)\right)^5=\\\\5\left(((1+i)^2)/(2)\right)^6+6\left(((1-i)^2)/(2)\right)^5=\\\\5\cdot ((1+i)^(12))/(64)+6\cdot ((1-i)^(10))/(32)=\\\\5\cdot (-64)/(64)+6\cdot (-32i)/(32)=\\\\-5-6i`