Question

What is the solution to the equation (Y/y-4) - (4/y+4) = (32/y^2-16)

Answer 1

y2 = −(−4) + √ (−4)2 − 4×9×(−32) 2×9 = 4 + 4 × √ 73 18 ≈ 2.121 If im wrong you have the right to slap me in the face

Answer 2

No solution

Explanation:

`(y)/(y-4) -(4)/(y+4)=(32)/(y^2-16)`

LEts factor y^2-16 to find out LCD

`y^2-16= y^2-4^2= (y+4)(y-4)`

`(y)/(y-4) -(4)/(y+4)=(32)/( (y+4)(y-4))`

LCD is (y+4)(y-4)

Multiply each fraction with LCD

`y(y+4)-4(y-4)= 32`

`y^2+4y-4y+16= 32`

Subtract 32 from both sides and combine like terms

`y^2-16= 0`

`(y+4)(y-4)= 0`

SEt each factor =0 and solve for y

`y+4=0 , y= -4`

`y-4=0 , y=4`

So the value of y are -4 and 4

When y=4 and -4 the denominator of original function becomes 0 that is undefined. so y values are not solutions for the given equation

No Solution for this equation