Please, please help me! I don't even know where to start with solving this... sec(x)csc(x)+√2 csc(x)=0

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asked Mar 14, 2019 207k views

1 Answer

SAVAFA · Answer 1 · 2019-03-21T16:24:18+0000

Factorize the left hand side and equate the factors to zero.

Then, use the notation that : sec x = 1/cosx and csc x = 1/sinx

Result: x = ± π3 + 2πk , k∈Z

Please, please help me! I don't even know where to start with solving this... sec(x)csc(x)+√2 csc(x)=0

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