Question

What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3 ? y+6=1/3(x+2) y+2=1/3(x+6) y−2=1/3(x−6) y−6=1/3(x−2)

Answer 1

y+6=13(x+2)

Explanation:

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Answer 2

y + 6 =
`(1)/(3)` (x + 2)

The equation of a line in ' point-slope form ' is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m =
`(1)/(3)` and (a , b ) = ( - 2, - 6)

y + 6 =
`(1)/(3)` (x + 2) → equation in point- slope form