Question

Identify the vertex, focus, and directrix of the parabola who’s equation is y^2=2x

Answer 1

y² = 2x ⇒ x =
`(1)/(2) y^(2)`

vertex (0, 0)

focus:
`(1)/(4p) = (1)/(2)` ⇒ p =
`(1)/(2)` so focus is: (
`(1)/(2)` , 0)

directrix: x =
`-(1)/(2)`