asked 224k views
3 votes
There are 11 foregin invaders and 4 lysosome in cell a if it takes each lysosome 1 h to digest 1 foreign invader, how long will it take to digest all of the foreign invaders

asked
User Clam
by
8.0k points

2 Answers

2 votes

Answer:

4 lysosomes takes 2 hr 45 mins to digest 11 foreign invader

Step-by-step explanation:

Given data:

No. of foreign invader is 11

Total number of lysosome is 4

If 1 hr is used for foreign invader then

From the data we have following

If 1 lysosomes take 1 hr to digest 1 foreign invader

Then

4 lysosomes take 1/4 hr to digest one foreign invaders

Therefore

4 lysosomes takes 11/4 hr to digest 11 foreign invader

11/4 mean = 2 3/4 hr i.e 2 hr 45 mins.

answered
User Newgennerd
by
8.0k points
5 votes

The correct answer is 3 hours.

During the first hour, all of the 4 lysosomes will digest 4 foreign invaders.

During the second hour another 4 foreign invaders will be digested.

The remaining 3 foreign invaders will be digested by 3 lysosomes during the third hour.


answered
User Boggio
by
8.6k points
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