Question

(8v3-80v2+6)\(v-10)

Answer 1

`((8v^3-80v^2+6))/(v-10)`

Use long division for dividing

`(8v^3-80v^2+6)` Here 'v' term is missing so we use 0vW

Divide
`(8v^3-80v^2+0v+6)` by v-10 using long division

Step 1: Put 8v^2 at the top

step 2: multiply 8v^2 with v-10 and put it at the bottom

step 3: subtract it

We will get remainder 6

so quotient is
`8v^2`

Remainder is 6