Question

in the given kite SZ= 10yards , WZ = 10 yards TZ=12 yards , and RZ=32 yards Determine the area of the kite

Answer 1

If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:

... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)

... A = 440 yd²