Question

Starting at home Omar traveled a pill to the gift store for 30 minutes such as 10 mph event travels back home along the same path down hill at a speed of 30 mph what is his average speed for the entire trip from home to the gift store and back

Answer 1

We know Distance formula is Distance = speed * time

`time = (distance)/(speed)`

Let, the distance Omar traveled = d and speed is 10 miles per hour

Time taken t for the first trip
`t = (d)/(10)`

Let, the distance Omar traveled = d and speed is 30 miles per hour

Time taken t for the return trip
`t = (d)/(30)`

Total time taken =
`(d)/(10) + (d)/(30) = (3d+d)/(30) = (4d)/(30)`

Now,
`Average \ speed = (total \  distance)/(total \ time \ taken)`

Total distance = d+d= 2d

Average speed =
`(2d)/((4d)/(30))` =
`2d * (30)/(4d) = 15`

His average speed for the entire trip from home to the gift store and back is

15 miles per hour