Register

How to factor (9x^2-3x-2)(x^2-6)

How to factor (9x^2-3x-2)(x^2-6)
asked 65.0k views
3 votes
How to factor (9x^2-3x-2)(x^2-6)

asked
User Tony Wang
by
7.8k points

1 Answer

0 votes


(9x^2-3x-2)(x^2-6)=(9x^2-6x+3x-2)(x^2-(\sqrt6)^2)\\\\=[3x(3x-2)+1(3x-2)](x-\sqrt6)(x+\sqrt6)\\\\=(3x-2)(3x+1)(x-\sqrt6)(x+\sqrt6)\\\\Used:\ a^2-b^2=(a-b)(a+b)

answered
User Cormac Driver
by
8.0k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!