Question

the length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimeter of the rectangle is 68 feet, what are the dimension ( the length and width) of the rectangle?

Answer 1

Represent the length and width by L and W. Then L = W + 4.

Using the perimeter formula: P = 2L + 2W = 68 ft = 2W) + 2(W+4).

Solve for W: 68 = 2W + 2W + 8, or 4W = 60. Thus, W = 15 and L = 19.

The dimensions of the rectangle are 15 by 19 feet.