Question

When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperature in celsius?

Answer 1

25.2°C

Step-by-step explanation:

Given parameters:

Energy applied to the water = 1000J

Mass of water = 50g

Final temperature = 30°C

Unknown:

Initial temperature = ?

Solution:

To solve this problem, we use the expression below:

H = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

1000 = 50 x 4.184 x (30 - initial temperature )

1000 = 209.2(30 - initial temperature)

4.78 = 30 - initial temperature

4.78 - 30 = - initial temperature

Initial temperature = 25.2°C