Question

Now assume that a satellite of mass m is orbiting the earth at a distance r from the center of the earth with speed ve. an identical satellite is orbiting the moon at the same distance with a speed vm. how does the time tm it takes the satellite circling the moon to make one revolution compare to the time te it takes the satellite orbiting the earth to make one revolution?

Answer 1

The answer is Tm= 2.pi.r / Vm and Tm is greater than Te.

Step-by-step explanation:

V = Sqrt (GM/r)

Vm = sqrt (Gme/r)

The time taken by satellite,

Te = 2. pi. r / Ve

Tm = 2 . pi. r / Vm.

Hence, Tm is greater.