Question

What is the solutions to the equation?

Answer 1

Hi,

Solving:


`x^(3) + 3x^(2) - 4x - 12 = 0 \\ {x}^(2) * (x + 3) - 4x - 12 = 0 \\ {x}^(2) * (x + 3) - 4(x - 3) = 0 \\ (x + 3) * ( {x}^(2) - 4) = 0 \\ x + 3 = 0 \\ {x}^(2) - 4 = 0 \\ \\ (results) \\ x1 = - 3 \\ x2 = - 2 \\ x3 = 2`

Hope this helps.
r3t40