Question

A fluid in an aquifer is 23.6 m above a reference datum, the fluid pressure (in gage pressure) is 4390 n/m2 and the flow velocity is 7.22 x 10-4 m/s. the fluid density is 0.999 x 103 kg/m3. using the bernoulli relationship (including velocity), calculate the (a) total energy per unit mass, and (b) total energy per unit weight. report your answer in units of meters and seconds. assume that g = 9.8 m/s2.

Answer 1

As per Bernuolli's Theorem total energy per unit mass is given as

`(P)/(\rho) + (1)/(2)v^2 + gH = E`

now from above equation

`P = 4390 N/m^2`

`\rho = 0.999 * 10^3`

`v = 7.22 * 10^(-4) m/s`

`H = 23.6 m`

now by above equation

`(4390)/(0.999*10^3) + (1)/(2)*(7.22*10^(-4))^2 + 9.8*23.6 = E`

`E = 235.7 J/kg`

Part B)

Now energy per unit weight

`U = (E)/(g)`

`U = (235.7)/(9.8)`

`U = 24 m`