Question

jason mixed 8ml of a salt solution with 11ml of a 47% salt solution to make a 43%salt solution. find the percent salt concentration of the first solution

Answer 1

Let x% be the salt concentration of first solution.

Then in 8ml, amount of salt =
`(8x)/(100)`

Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.

amount of salt in 11ml of 47% salt solution is
`(11*47)/(100)` =
`(517)/(100)`

So, total amount of salt in new mixture =
`(8x)/(100) +(517)/(100) = (8x+517)/(100)`

But given that this new solution is a 43% salt solution.

Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is
`(19*43)/(100) = (817)/(100)`

Hence
`(8x+517)/(100) = (817)/(100)`

8x+517 = 817

8x=817-517 = 300

x= 300/8 = 37.5

Hence the salt concentration in the first solution is 37.5%