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Please help me with this!

Choose the right system for each equation(picture)
Picture one: Inconsistent, consistent, or equivalent?
Picture two: Inconsistent, consistent, or equivalent?
picture three: Inconsistent, consistent, or equivalent?
picture four: Inconsistent, consistent, or equivalent?
picture five: Inconsistent, consistent, or equivalent?

Please help me with this! Choose the right system for each equation(picture) Picture-example-1
Please help me with this! Choose the right system for each equation(picture) Picture-example-1
Please help me with this! Choose the right system for each equation(picture) Picture-example-2
Please help me with this! Choose the right system for each equation(picture) Picture-example-3
Please help me with this! Choose the right system for each equation(picture) Picture-example-4
Please help me with this! Choose the right system for each equation(picture) Picture-example-5

2 Answers

3 votes

pic 1: equivalent

pic 2 : consistent

pic 3: consistent

pic 4: inconsistent

pic 5: equivalent.

number 6 incase you have it y=3x-2, 3x-y=4 :inconsistent

Explanation:

consistent means they share a point, equivalent is when they have infinite or many touching points so basically the same line. And inconsistent means no sharing points so two different lines.

answered
User Ashey
by
8.4k points
4 votes

1. The first equation is - 2x + 5y = 0

Second equation is
y = (2)/(5) x

5y = 2x

- 2x + 5y = 0

Hence, the two equations are equivalent.

2.
a_(1) = 2, a_(2) = - 2


b_(1) = -1,  b_(2) = -1


(a_(1) )/(a_(2)) =(2)/(-2) = -1


(b_(1) )/(b_(2)) = (-1)/(-1)  = 1


(a_(1) )/(a_(2)) \\eq (b_(1) )/(b_(2))

Hence, the equations are consistent.

3.
a_(1) = 4, a_(2) = 6


b_(1) = -1, b_(2) = -1


(a_(1) )/(a_(2)) =(4)/(6) = (2 )/(3)


(b_(1) )/(b_(2)) = (-1)/(-1) = 1


(a_(1) )/(a_(2)) \\eq (b_(1) )/(b_(2))

Hence, the equations are consistent.

4. Equations can be re-arranged as:

x + y - 4 = 0 and

x + y + 6 = 0


a_(1) = 1, a_(2) = 1


b_(1) = 1, b_(2) = 1


c_(1) = -4, c_(2) = 6


(a_(1) )/(a_(2)) =(1)/(1) = 1


(b_(1) )/(b_(2)) =(1)/(1) = 1


(c_(1) )/(c_(2)) =(-4)/(6) = (-2)/(3)


(a_(1) )/(a_(2)) = (b_(1) )/(b_(2)) \\eq (c_(1) )/(c_(2))

Hence, the equations are inconsistent.

5. If we multiply the first equation by 4, we will get,

2y = -4x + 20 which is the second equation.

Hence, the equations are equivalent.

answered
User Greg Wilson
by
7.4k points

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