Question

Find the distance cd rounded to the nearest tenth. c=(6,-5) and D=(-1,-4)

Answer 1

`\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ C(\stackrel{x_1}{6}~,~\stackrel{y_1}{-5})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-4})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ CD=√([-1-6]^2+[-4-(-5)]^2)\implies CD=√((-1-6)^2+(-4+5)^2) \\\\\\ CD=√((-7)^2+1^2)\implies CD=√(49+1) \\\\\\ CD=√(50)\implies CD\approx 7.0710678\implies CD=\stackrel{\textit{rounded up}}{7.1}`