Question

PLEASE HELP ME FAST

A submarine left Hawaii two hours before an aircraft carrier. The vessels traveled in opposite directions. The aircraft carrier traveled at 25 mph for nine hours. After this time the vessels were 280 mi. apart. Find the submarine's speed.

Answer 1

D = r*t

Let x represent the submarines speed.

Question states*** 280mi apart after traveling opposite direction

11hr*x + 25mph*9hr = 280mi |note:submarine left Hawaii two hours before an aircraft carrier

Solving for x

11hrx = 55mi

x = 5mph, the submarine's speed