What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 22 ∘c?

Question

asked Jul 12, 2019 4.7k views

1 Answer

Deekshith Bellare · Answer 1 · 2019-07-19T04:41:26+0000

solution:

1000 = m*2400*(78-22) + m*8.79*10^5

1000= 134400m + 879000m

1000= 1030200m

m = 1000/1013400

m= 1013.4 grams

the final answer is 0.9706 grams