Question

Maria and Tim sold candy bars for a fundraiser. Maria sold seven less than twice the number of candy bars that Tim sold. in total, Maria and Tim sold 137 candy bars. How many candy bars did Maria sell?

Answer 1

Maria's candy bars can be substituted by x

Therefore, Tim's total number of candies is 2x-7 (twice the amount of x, 7 less)

137 is the total number of candies sold by both, so x+2x-7 is 137.

By gathering like terms, 3x-7 must equal 137

Then, add 7 to both sides, so 3x is 144

To find x, divide both sides by 3

x=48

So, Maria sells 48 candies

Tim sells 2*48-7 candies, which is 89 candies

Answer 2

Answer: Maria sold 89 candies.

Explanation:

Let x be the number of candies sold by Maria and y be the number of candies sold by Tim.

Given : Maria sold seven less than twice the number of candy bars that Tim sold. in total, Maria and Tim sold 137 candy bars.

`x=2y-7------(i)\\\\x+y=137--------(ii)`

Substitute the value of x from (i) in (ii), we get

`2y-7+y=137\\\\\Rightarrow\ 3y=137+7\\\\\Rightarrow\ 3y=144\\\\\Rightarrow\ y=(144)/(3)=48`

Put value of y in (i), we get

`x=2(48)-7=96-7=89`

Hence, Maria sold 89 candies.