Question

What is the length of the hypotenuse, x f (20, 21, x) is a Pythagorean triple

Answer 1

B) - 29

Explanation:

Answer 2

`\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=√(a^2+b^2) \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{20}\\ b=\stackrel{opposite}{21}\\ \end{cases} \\\\\\ x=√(20^2+21^2)\implies x=√(841)\implies x=29`