Question

G(x)=1/2(x-3)+1 find the inverse

Answer 1

`g(x)=(1)/(2)(x-3)+1\\\\y=(1)/(2)(x-3)+1\\\\\text{replace x with y and y with x}\\\\x=(1)/(2)(y-3)+1\\\\\text{solve for y}\\\\(1)/(2)(y-3)+1=x\ \ \ \ |-1\\\\(1)/(2)(y-3)=x-1\ \ \ \ |\cdot2\\\\y-3=2x-2\ \ \ \ |+3\\\\y=2x+1\\\\Answer:\ \boxed{g^(-1)(x)=2x+1}`