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Twice a number increased by 3 is less than the number decreased by 4

1 Answer

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Set it up like this: 2n+3 < n-4

Solve for n:

2n+3 < n-4

-n -n (1st step: get n on one side by itself)

n+3 < -4

-3 -3 (2nd step: subtract 3 from both sides)

n < -7

The answer is n < -7

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User Hsinxh
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