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Please help!!! How do you count (-3y^2+5y) (4y+7)??

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User Sild
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1 Answer

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You must distribute each value like this:


(-3y^2+5y) (4y+7)\\ \\ (-12y^3-21y^2+20y^2+35y)\\ \\ (-12y^3-y^2+35y)

Hope that helps!

answered
User Tim Schwalbe
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