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Find a number that is 68 greater than three times its opposite

1 Answer

4 votes

These are fun! Let's make a math sentence.

Our number is x.

We are told that x is equal to 68 more than 3 (-x)

x=3(-x) + 68 is our final equation

Now solve.

x = -3x + 68 Subtract -3x from both sides to move the variables to the left.

x -(-3x) = 68 Change the two minuses to a plus

x+3x = 68 Add the variables

4x = 68 Divide both sides by 4 to leave only x.

x = 17

answered
User Aaran McGuire
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