Question

Asimtot tegak fungsi h(x) = cos x / sin 2x adalah

Answer 1

We have been given a trigonometric function and we need to determine its vertical asymptotes.

We have,
`h(x)=(cos(x))/(sin(2x))`

We can find its vertical asymptotes by setting the denominator equal to zero.

`sin(2x)=0\\ 2x=n\pi \\ \\ x=(n\pi)/(2)`

Therefore, vertical asymptotes of the given function occur at
`x=(n\pi)/(2)`, Where n is any integer.