Question

Please help me with this math problem.

Answer 1

If we plug the values, we have

`f(2) = 2p+3,\ g(5) = 5+4p`

So, we have to solve the following equation:

`2p+3 = 5+4p \iff -2p=2 \iff p = -1`

So, when we impose
`f(x) = g(x)`, knowing the value of p, we have

`f(x) = -x+3 = x-4 = g(x)`

And so the solution is

`-x+3 = x-4 \iff -2x = -7 \iff x = (7)/(2)`