Question

A half-acre building lot is five times as long as it is wide. What are its dimensions?

Answer 1

we know that

A half-acre is equal to---------->
`2,023.43\ m^(2)`

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

`A=2,023.43\ m^(2)`

`A=x*y`

`2,023.43=x*y` --------> equation 2

substitute equation 1 in equation 2

`2,023.43=[5y]*y`

`5y^(2)= 2,023.43\\y^(2)= 404.686\\y= 20.11\ m`

Find the value of x

`x=5y---> x=5*20.11--> x=100.55 m`

therefore

the answer is

the dimensions of the building lot are 100.55 m* 20.11 m