Let n be the smaller integer.
Step 2. Let n+1 be the larger and next consecutive integer.
Step 3. Let 3n be three times the smaller integer.
Step 4. Let 4(n+1) be four times the larger integer.
Step 5. Then 3n+4(n+1)=39 since three times the smaller of two consecutive integers is added to four times the larger will result in 39.
Step 6. Solving the equation in Step yields the following steps:
stWith n=5, then n+1=6 and check the sum 3*5+4*6=15+24=39...which is a true statement.
Step 7. ANSWER: The integers are 5 and 6
I hope the above steps were helpful.heyaaa
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