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A random sample of 12 lunch orders at noodles and company showed a mean bill of $12.99 with a standard deviation of $4.6. find the 98 percent confidence interval for the mean bi…

A random sample of 12 lunch orders at noodles and company showed a mean bill of $12.99 with a standard deviation of $4.6. find the 98 percent confidence interval for the mean bi…
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A random sample of 12 lunch orders at noodles and company showed a mean bill of $12.99 with a standard deviation of $4.6. find the 98 percent confidence interval for the mean bill of all lunch orders. (round your answers to 4 decimal places.)

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User Dominic Price
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1 Answer

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12.99 + 4.6 = 17.59 / 98
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User Ramonita
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